Solve each problem 1)x-27=-(27-x)2)6y-8=2(3y-4)Thank you in advance

Answer:1) x ∈ R2) y ∈ RStep-by-step explanation:* Lets explain something very important when we solve an equation  of one variable- If we have an equation of x then the solution is one of these cases# x has only one value# x has no value # x can be any value- The first case when we solve for x and the answer is one value- The second when x disappear and the left hand side of the   equation not equal the right hand side- The third when x disappear and the left hand side of the   equation equal the right hand side* Lets solve the problem1)∵ x - 27 = -(27 - x)- Multiply the bracket (27 - x) by (-)- Remember (-)(+) = (-) and (-)(-) = (+)∴ x - 27 = -27 + x- Subtract x from both sides and add 27 to both sides∴ x - x = -27 + 27∴ 0 = 0∵ The left hand side = the right hand side∴ x can be any real number∴ x ∈ R ⇒ R is the set of real number2) ∵ 6y - 8 = 2(3y - 4)- Multiply the bracket (3y - 4) by 2∴ 6y - 8 = 6y - 8- Subtract 6y from both sides and add 8 to both sides∴ 6y - 6y = -8 + 8∴ 0 = 0∵ The left hand side = the right hand side∴ y can be any real number∴ y ∈ R ⇒ R is the set of real number