Kayla's school is selling tickets to a play. On the first day of ticket sales, the school sold 5 senior citizen tickets and 3 child tickets for a total of $69. The school took in $73 on the second day by selling 1 senior citizen ticket and 8 child tickets. Find the price of a senior citizen ticket and the price of a child ticket

Answer:Senior Citizen Tickets Cost = $9Child Tickets Cost = $8Step-by-step explanation:Let price of senior ticket be "s", andprice of child ticket be "c"5 senior ticket and 3 child ticket cost 69, so we can write:[tex]5s+3c=69[/tex]Also, 1 senior and 8 child tickets cost 73, thus we can write:[tex]s+8c=73[/tex]Or[tex]s=73-8c[/tex]We can put this into 1st equation and get an equation in terms of "c" and solve for c first:[tex]5s+3c=69\\5(73-8c)+3c=69\\365-40c+3c=69\\296=37c\\c=8[/tex]Thus, c = 8Now, s = 73 - 8cs = 73 - 8(8)s = 73 - 64s = 9So,Senior Citizen Tickets Cost = $9Child Tickets Cost = $8