MATH SOLVE

2 months ago

Q:
# how do i do these inverse trig

Accepted Solution

A:

This is a right triangle

so

Cos x = 109 / 134 then x = cos⁻¹ (109/134) = 35.567°

sin y = 109 / 134 then y = sin⁻¹ (109/134) = 54.433°

and

the third side = √(134² - 109²) = 77.94

so

Cos x = 109 / 134 then x = cos⁻¹ (109/134) = 35.567°

sin y = 109 / 134 then y = sin⁻¹ (109/134) = 54.433°

and

the third side = √(134² - 109²) = 77.94