Does the following equation determine y to be a function of x? y square=x+3

Answer:∴ y² = x + 3 is not a functionStep-by-step explanation:* Lets explain how to solve the problem- The definition of the function is every input (x) has only one   output (y)- Ex: # y = x + 1 where x ∈ R , is a function because every x has only   one value of y# y² = x where x ∈ R , is not a function because y = ±√x, then one   x has two values of y* Lets solve the problem∵ y² = x + 3- Find y by taking √ for both sides∴ y = ± √(x + 3)- That means y = √(x + 3)  and y = - √(x + 3)∵ (x + 3) must be greater than or equal zero because there is no   square root for negative number∴ x + 3 ≥ 0 ⇒ subtract 3 from both sides∴ x ≥ -3∴ x must be any number greater than or equal -3- Let x = 0∴ y = √(0 + 3) = √3 and y = - √(0 + 3) = -√3∴ x = 0 has two values of y ⇒ y = √3 and y = -√3- Any value of x greater than or equal 3 will have two values of y ∴ y² = x + 3 is not a function